document.write( "Question 66819This question is from textbook Advanced mathematics
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document.write( ": Evaluate:
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document.write( "A.) Arcsin [ -(square root of 3)/2]\r
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document.write( "B.) sin [ Arccos (-3/4) ]\r
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Algebra.Com's Answer #47557 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! Evaluate: \n" ); document.write( "A.) Arcsin [ -(square root of 3)/2]=X SAY \n" ); document.write( "SIN(X)=-SQRT(3)/2=-SIN(60)=SIN(180+60)=SIN(240)...OR... \n" ); document.write( "...SIN(360-60)=SIN(300) \n" ); document.write( "HENCE X=240 OR 300....GENERAL FORMULA IS \n" ); document.write( "240,240+360,240+2*360......240+N*360.OR \n" ); document.write( "300,300+360,300+2*360....300+N*360\r \n" ); document.write( "\n" ); document.write( "B.) sin [ Arccos (-3/4) ] = \n" ); document.write( "LET ARCCOS(-3/4)=Y.....WE HAVE TO FIND SIN(Y)=? \n" ); document.write( "COS(Y)=-3/4..THAT IS Y IS IN II OR III QUADRANTS \n" ); document.write( "SIN(Y)=SQRT[1-COS^2(Y)]=SQRT[1-9/16]=SQRT(7/16)=[SQRT(7)]/4 \n" ); document.write( "IF Y IS IN II QUADRANT THEN ANSWER IS [SQRT(7)]/4 \n" ); document.write( "IF Y IS IN III QUADRANT THEN ANSWER IS -[SQRT(7)]/4 \n" ); document.write( " |