document.write( "Question 780186: A box with an open top has a square base and four sides of equal height. The volume of the box is 200 ft cubed. The height is three feet greater than both the length and width. If the surface area is 185 ft squared, what are the dimensions of the box? \n" ); document.write( "
Algebra.Com's Answer #475562 by ankor@dixie-net.com(22740)\"\" \"About 
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A box with an open top has a square base and four sides of equal height.
\n" ); document.write( " The volume of the box is 200 ft cubed. The height is three feet greater than both the length and width.
\n" ); document.write( " If the surface area is 185 ft squared, what are the dimensions of the box?
\n" ); document.write( ":
\n" ); document.write( "Let s = the length of the sides of the square bottom
\n" ); document.write( "then
\n" ); document.write( "(s+3) = the height
\n" ); document.write( ":
\n" ); document.write( "Surface area:
\n" ); document.write( "4(s(s+3)) + s^2 = 185
\n" ); document.write( "4s^2 + 12s + s^2 - 185 = 0
\n" ); document.write( "A quadratic equation
\n" ); document.write( "5s^2 + 12s - 183 = 0
\n" ); document.write( "You can use the quadratic formula to find s, but this will factor to
\n" ); document.write( "(5s+37)(s-5) = 0
\n" ); document.write( "The positive solution is all we want here
\n" ); document.write( "s = 5 ft is the length of the square sides
\n" ); document.write( "then
\n" ); document.write( "5 + 3 = 8 ft is the height
\n" ); document.write( ":
\n" ); document.write( "Check by finding the volume
\n" ); document.write( "V = 5 * 5 * 8
\n" ); document.write( "V = 200 cu/ft \n" ); document.write( "
\n" );