document.write( "Question 779818: an automobile radiator holds 15 liters of fluid. There is currently a mixture in the radiator that is 70% antifreeze and %30 water. How much of this mixture should be drained and replaced by pure antifreeze so that the resulting mixture is %80 antifreeze? \n" ); document.write( "

Algebra.Com's Answer #475448 by lwsshak3(11628) $\"\"$ $\"About$

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an automobile radiator holds 15 liters of fluid. There is currently a mixture in the radiator that is 70% antifreeze and %30 water. How much of this mixture should be drained and replaced by pure antifreeze so that the resulting mixture is %80 antifreeze?
\n" ); document.write( "***
\n" ); document.write( "x=amount of current mixture to be drained and replaced by pure antifreeze.
\n" ); document.write( "70%(15-x)+100%x=80%(15)
\n" ); document.write( "10.5-0.7x+x=12
\n" ); document.write( "0.3x=1.5
\n" ); document.write( "x=5
\n" ); document.write( "amount of current mixture to be drained and replaced by pure antifreeze: 5 liters \n" ); document.write( "

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