document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=779933>Question 779933</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length and width of a rectangle are in the ratio 4 to 3.The area is 192.Find the length and width.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #475420 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=475420\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The length and width of a rectangle are in the ratio 4 to 3.The area is 192.Find the length and width.<BR>\n" );
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document.write( "4:3 is the same as 4x:3x where 4x is the length and 3x is the width.<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "4x*3x = 192<BR>\n" );
document.write( "12x^2 = 192<BR>\n" );
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document.write( "x^2 = 18<BR>\n" );
document.write( "x = 3sqrt(2)<BR>\n" );
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document.write( "length = 4x = 12sqrt(2<BR>\n" );
document.write( "width = 3x = 9sqrt(2)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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