document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=779803>Question 779803</A>: <I><SPAN STYLE=\"word-break: break-all;\"> \" How do I factor this trinomoial using the ac method?\" please break it down and explain thank you.\r<BR>\n" );
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document.write( "15x^2-7x-2<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #475404 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=475404\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> factor this trinomoial using the ac method?\" please break it down and explain thank you. <BR>\n" );
document.write( "15x^2-7x-2<BR>\n" );
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document.write( "AC = 15*-2 = -30<BR>\n" );
document.write( "B = -7<BR>\n" );
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document.write( "Find 2 factors of -30 whose sum = -7<BR>\n" );
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document.write( "The factors are -10 and 3<BR>\n" );
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document.write( "Rewrite the problem substituting -10x+3x for -7x:::<BR>\n" );
document.write( "15x^2 -10x+3x -2<BR>\n" );
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document.write( "Factor the 1st two and the last two terms seperately::<BR>\n" );
document.write( "5x(3x-2)+ (3x-2)<BR>\n" );
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document.write( "Factor again:<BR>\n" );
document.write( "(3x-2)(5x+1)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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