document.write( "Question 779792: If I roll 5 regular dice out of a cup (and continuously re-roll; meaning roll then pick up all the dice and restart, pick up / restart, etc.), what is the probability of getting \"5 of a kind\" within 1,296 attempts (including the 1,296th roll)? \r
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document.write( "I tried this:
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document.write( "x = Probability of NOT rolling \"5 of a kind\" within 1,296 attempts = (1295/1296)^1296≈0.37\r
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document.write( "Probability of rolling \"5 of a kind\" within 1,296 attempts = 1 - x ≈ 0.63
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Algebra.Com's Answer #475403 by edjones(8007)![]() ![]() You can put this solution on YOUR website! You are correct. \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( " |