document.write( "Question 66884: How many pounds of a 35% salt solution and how many pounds of a 14% salt solution should be combined so that 50 pounds of a 20% salt solution are obtained? \n" ); document.write( "

Algebra.Com's Answer #47540 by ptaylor(2198) $\"\"$ $\"About$

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\n" ); document.write( "Let x=number of pounds of 35% solution
\n" ); document.write( "Then 50-x=number of pounds of 14% solution\r
\n" ); document.write( "\n" ); document.write( "Now we know that the pure salt in the 35% solution (.35x) plus the amount of pure salt in the 14% solution (.14(50-x)) has to equal the amount of pure salt in the final mixture (.20(50). So our equation to solve is:\r
\n" ); document.write( "\n" ); document.write( ".35x+.14(50-x)=.20(50) multiplying out:\r
\n" ); document.write( "\n" ); document.write( ".35x+7-.14x=10 subtract 7 from both sides \r
\n" ); document.write( "\n" ); document.write( ".35x+7-7-.14x=10-7 collect like terms
\n" ); document.write( ".21x=3
\n" ); document.write( "x=14.285 lb -------------number of pounds of 35% solution\r
\n" ); document.write( "\n" ); document.write( "50-x=50-14.285=35.715-------------number of pounds of 14% solution\r
\n" ); document.write( "\n" ); document.write( "Ck\r
\n" ); document.write( "\n" ); document.write( "substitute into original equation
\n" ); document.write( ".35(14.285)+.14(35.715)=.20(50)
\n" ); document.write( "5+5=10
\n" ); document.write( "10=10\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps-----ptaylor\r
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