document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=66850>Question 66850</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 7(4W-3)-25W CAN YOU HELP ME SOLVE THIS?I have <BR>\n" );
document.write( "7.4w-3-25<BR>\n" );
document.write( "28-21-25 now i am lost </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #47537 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=47537\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 7(4w-3)-25w you need to multiply 4w*7 & -3*7 thus 4w*7=28w & -3*7=-21 then combine the w terms<BR>\n" );
document.write( "28w-21-25w<BR>\n" );
document.write( "28w-25w-21<BR>\n" );
document.write( "3w-21 now factor out 3 which is common to both terms.<BR>\n" );
document.write( "3(w-7) </SPAN>\n" );
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