document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=779763>Question 779763</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the equation: (x/x-3)+(3/x+3)=6x/x^2-9       I kind of had an idea of how to approach this problem by the lowest common denominator but the right side threw me off. If you could help that would be awesome </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #475349 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=475349\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (x/x-3)+(3/x+3)=6x/x^2-9 <BR>\n" );
document.write( "Lowest common denominator = x^2-9<BR>\n" );
document.write( "This is because x^2-9 = (x + 3)(x - 3)<BR>\n" );
document.write( "x(x + 3) + 3(x - 3) = 6x<BR>\n" );
document.write( "x^2 + 3x + 3x - 9 = 6x<BR>\n" );
document.write( "Collect like terms.<BR>\n" );
document.write( "x^2 + 3x + 3x - 6x - 9 = 0<BR>\n" );
document.write( "x^2 - 9/x^2 - 9<BR>\n" );
document.write( "= 1<BR>\n" );
document.write( "Hope this helps.<BR>\n" );
document.write( ":-) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );