document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=779649>Question 779649</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The measure of an angle is 10 more than the measure of its complement.Find the measure of each angle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #475310 by </B><A HREF=/tutors/aboutme.mpl?userid=Anigor+><B>Anigor (1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Anigor+><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=475310\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Complementary angles have a sum of 90°\r<BR>\n" );
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document.write( "let x = measure of an angle<BR>\n" );
document.write( "    90-x = measure of its complement\r<BR>\n" );
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document.write( "x = (90-x) + 10<BR>\n" );
document.write( "x = 100 - x<BR>\n" );
document.write( "x + x = 100<BR>\n" );
document.write( "2x = 100<BR>\n" );
document.write( "2x/2 = 100/2 (divide both sides by 2 to isolate x) <BR>\n" );
document.write( "x = 50° (MEASURE OF FIRST ANGLE)\r<BR>\n" );
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document.write( "90-x = ?<BR>\n" );
document.write( "90-50 = 40° (substitute value of x which is 50 to get the COMPLEMENTARY ANGLE)\r<BR>\n" );
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document.write( "50° + 40° = 90°   </SPAN>\n" );
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