document.write( "Question 779623: 30 men can do a work in 36 days. After 30 days more men are employed and work is done 2 days before . Find no of more men employed?
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Algebra.Com's Answer #475302 by josmiceli(19441) $\"\"$ $\"About$

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What fraction of the work gets done in 30 days?
\n" ); document.write( "( 30 days ) / ( 36 days ) = $\"+5%2F6+\"$ gets done
\n" ); document.write( "That leaves $\"+1%2F6+\"$ left to do
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\n" ); document.write( "So, there are $\"+6+\"$ days left to do $\"+1%2F6+\"$
\n" ); document.write( "of the job
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\n" ); document.write( " $\"+1%2F6+\"$ of the job actually gets done in $\"+6+-+2+=+4+\"$ days
\n" ); document.write( "-----------------
\n" ); document.write( " $\"+30+\"$ men can do a work in $\"+36+\"$ days.
\n" ); document.write( " $\"+1+\"$ man can do the work in $\"+30%2A36+=+1080+\"$ days
\n" ); document.write( "-----------------
\n" ); document.write( "Let $\"+n+\"$ = number of men needed to do $\"+1%2F6+\"$
\n" ); document.write( "of the job in $\"+4+\"$ days
\n" ); document.write( " $\"+n%28+1%2F1080+%29+=+%28+1%2F6+%29+%2F+4+\"$
\n" ); document.write( " $\"+n%2F1080+=+1%2F24+\"$
\n" ); document.write( " $\"+n+=+1080%2F24+\"$
\n" ); document.write( " $\"+n+=+45+\"$
\n" ); document.write( "----------------
\n" ); document.write( "There are already $\"+30+\"$ men working, so
\n" ); document.write( " $\"+45+-+30+=+15+\"$ more men are needed\r
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