document.write( "Question 779604: The length of rectangle is 5 cm longer than its width and its area is 66 cm2. Find perimeter of the rectangle \n" ); document.write( "

Algebra.Com's Answer #475298 by mananth(16946) $\"\"$ $\"About$

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width be x
\n" ); document.write( "length = (x+5)\r
\n" ); document.write( "\n" ); document.write( "Area = L * W\r
\n" ); document.write( "\n" ); document.write( "x(x+5)=66\r
\n" ); document.write( "\n" ); document.write( "x^2+5x=66
\n" ); document.write( "x^2+5x-66=0\r
\n" ); document.write( "\n" ); document.write( "x^2+11x-6x-66=0\r
\n" ); document.write( "\n" ); document.write( "x(x+11)-6(x+11)=0\r
\n" ); document.write( "\n" ); document.write( "(x+11)(x-6)=0\r
\n" ); document.write( "\n" ); document.write( "x=-11 OR x=6\r
\n" ); document.write( "\n" ); document.write( "take the positive value\r
\n" ); document.write( "\n" ); document.write( "width = 6 cm\r
\n" ); document.write( "\n" ); document.write( "and length = x+5 ==>6+5=11cm\r
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