document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=779577>Question 779577</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The digit at ten's place of a two-digit number is three times the digit at unit's place. The number obtained by interchanging the digits is less than the original number by 36. Find the original number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #475294 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=475294\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the number be xy\r<BR>\n" );
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document.write( "x=3y....................(1)\r<BR>\n" );
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document.write( "10y+x=10x+y-36\r<BR>\n" );
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document.write( "9y-9x=-36<BR>\n" );
document.write( "/9<BR>\n" );
document.write( "y-x=-4..................(20\r<BR>\n" );
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document.write( "substitute x\r<BR>\n" );
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document.write( "y-3y=-4<BR>\n" );
document.write( "-2y=-4<BR>\n" );
document.write( "y=2\r<BR>\n" );
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document.write( "x=3y<BR>\n" );
document.write( "so x=6\r<BR>\n" );
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document.write( "The number is 62 </SPAN>\n" );
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