document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=779602>Question 779602</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help with this question. I really need help!!!<BR>\n" );
document.write( "a tourist rents a beach cruiser to bike along a flat stretch of beach. Biking with the wind it takes 9 minutes to travel 2 miles. Biking against the wind, the return trip takes 24 minutes. if there was no wind, how fast was the cyclist biking?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #475292 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=475292\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Convert minutes to hours\r<BR>\n" );
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document.write( "beach cruiser	speed	=x	mph					<BR>\n" );
document.write( "wind   	speed	=y	mph					<BR>\n" );
document.write( "against  	wind   	0.4	hours					<BR>\n" );
document.write( "with	wind   	0.15	hours					<BR>\n" );
document.write( "								<BR>\n" );
document.write( "Distance against 		2	miles	distance with 		2	miles	<BR>\n" );
document.write( "t=d/r	against	wind   		-				<BR>\n" );
document.write( "2.00	/	(	x	-	y	)=	0.40	<BR>\n" );
document.write( "0.40	(	x	-	y	)	=	0.15	<BR>\n" );
document.write( "0.40	x	-	0.40	y	=	2.00	....................1	<BR>\n" );
document.write( "								<BR>\n" );
document.write( "2.00	/	(	x	+	y	)=	0.15	<BR>\n" );
document.write( "0.15	(	x	+	y	)	=	2.00	<BR>\n" );
document.write( "0.15	x	+	0.15	y	=	2.00	...............2	<BR>\n" );
document.write( "Multiply (1) by	0.15							<BR>\n" );
document.write( "Multiply (2) by	0.40							<BR>\n" );
document.write( "we get								<BR>\n" );
document.write( "0.06	x	+	-0.06	y	=	0.30		<BR>\n" );
document.write( "0.06	x	+	0.06	y	=	0.80		<BR>\n" );
document.write( "0.12	x	=	1.10					<BR>\n" );
document.write( "/	0.12							<BR>\n" );
document.write( "x	=	9.17	mph					<BR>\n" );
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document.write( "plug value of x in (1)				y				<BR>\n" );
document.write( "0.40	x		-0.40	y	=	2.00		<BR>\n" );
document.write( "3.67			-0.40	-3.67	=	2.00		<BR>\n" );
document.write( "-0.40	y	=	2.00					<BR>\n" );
document.write( "-0.40	y	=	-1.67	mph				<BR>\n" );
document.write( "	y	=	4.17					<BR>\n" );
document.write( "beach cruiser	speed	9.17	mph					<BR>\n" );
document.write( "wind   	speed	4.17	mph					<BR>\n" );
document.write( "								<BR>\n" );
document.write( "m.ananth@hotmail.ca								     <BR>\n" );
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