document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=779579>Question 779579</A>: <I><SPAN STYLE=\"word-break: break-all;\"> whats is the answer for this formula ? <BR>\n" );
document.write( "A coffee merchant combines coffee that costs $6 per pound with coffee that costs $4.20 per pound. How many pounds of each should be used to make 22 lb of a blend costing $5.55 per pound? <BR>\n" );
document.write( "$6 per lb coffee    	  lb<BR>\n" );
document.write( "$4.20 per lb coffee    	  lb<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #475290 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=475290\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 	Price	----------------			quantity									<BR>\n" );
document.write( "Coffee Type I	$6.00	----------------			x	pounds								<BR>\n" );
document.write( "Coffe type II	$4.20	------	22	-	x	pounds								<BR>\n" );
document.write( "Mixture	$5.55	----------------	22											<BR>\n" );
document.write( "	22													<BR>\n" );
document.write( "6	x	+	4.2	(	22	-	x	)	=	122.1				<BR>\n" );
document.write( "6	x	+	92.4	-	4.2	x	=			122.1				<BR>\n" );
document.write( "6	x	-	4.2	x			=	122.1	-	-92.4				<BR>\n" );
document.write( "1.8	x			=	29.7									<BR>\n" );
document.write( "/	1.8													<BR>\n" );
document.write( "	x			=	16.5		pounds			$6.00		Coffee Type I		<BR>\n" );
document.write( "					5.5		pounds			$4.20		Coffee type II		<BR>\n" );
document.write( "														<BR>\n" );
document.write( "m.ananth@hotmail.ca														<BR>\n" );
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