document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=779518>Question 779518</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the length L of a rectangle is 3 meters more than twice its width and its perimeter is 300 meters. How do you solve the equation? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #475250 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=475250\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the length L of a rectangle is 3 meters more than twice its width and its perimeter is 300 meters. How do you solve the equation?<BR>\n" );
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document.write( "L = 2W+3<BR>\n" );
document.write( "W is the width<BR>\n" );
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document.write( "Perimeter = 2(L+W)<BR>\n" );
document.write( "300 = 2(2W+3 + W)<BR>\n" );
document.write( "150 = 3W+3<BR>\n" );
document.write( "3W = 147<BR>\n" );
document.write( "W = 49 meters (width)<BR>\n" );
document.write( "L = 2W+3 = 98+3 = 102 meters (length)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "============ </SPAN>\n" );
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