document.write( "Question 779326: Given the endpoints of a diameter of a circle at (4,1) and (-4,-4), find the center and radius of the circle. Write its equation in standard form.\r
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Algebra.Com's Answer #475205 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
if the endpoints of a \"diameter\" of a circle at (4,1) and (-4,-4), then the center is midpoint:\r
\n" ); document.write( "\n" ); document.write( "\"x\" coordinate of midpoint is \"%28x1%2Bx2%29%2F2=%284%2B%28-4%29%29%2F2=0%2F2=0\"\r
\n" ); document.write( "\n" ); document.write( "\"y\" coordinate of midpoint is \"%28y1%2By2%29%2F2=%281%2B%28-4%29%29%2F2=-3%2F2=-1.5\"\r
\n" ); document.write( "\n" ); document.write( "so, the center is at (\"0\",\"-1.5\") and it means \"h=0\" and \"k=-1.5\"\r
\n" ); document.write( "\n" ); document.write( "now find the length of radius which is equal to distance between one endpoint and midpoint of diameter\r
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Solved by pluggable solver: Distance Formula

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\n" ); document.write( " The first point is (x1,y1). The second point is (x2,y2)
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\n" ); document.write( " Since the first point is (0, -1.5), we can say (x1, y1) = (0, -1.5)
\n" ); document.write( " So \"x%5B1%5D+=+0\", \"y%5B1%5D+=+-1.5\"
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\n" ); document.write( " Since the second point is (4, 1), we can also say (x2, y2) = (4, 1)
\n" ); document.write( " So \"x%5B2%5D+=+4\", \"y%5B2%5D+=+1\"
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\n" ); document.write( " Put this all together to get: \"x%5B1%5D+=+0\", \"y%5B1%5D+=+-1.5\", \"x%5B2%5D+=+4\", and \"y%5B2%5D+=+1\"
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\n" ); document.write( " Now use the distance formula to find the distance between the two points (0, -1.5) and (4, 1)
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\n" ); document.write( " \"d+=+sqrt%28%28x%5B1%5D-x%5B2%5D%29%5E2+%2B+%28y%5B1%5D+-+y%5B2%5D%29%5E2%29\"
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\n" ); document.write( " \"d+=+sqrt%28%280+-+4%29%5E2+%2B+%28-1.5+-+1%29%5E2%29\" Plug in \"x%5B1%5D+=+0\", \"y%5B1%5D+=+-1.5\", \"x%5B2%5D+=+4\", and \"y%5B2%5D+=+1\"
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\n" ); document.write( " \"d+=+sqrt%28%28-4%29%5E2+%2B+%28-2.5%29%5E2%29\"
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\n" ); document.write( " \"d+=+sqrt%2816+%2B+6.25%29\"
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\n" ); document.write( " \"d+=+sqrt%2822.25%29\"
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\n" ); document.write( " \"d+=+4.7169905660283\"
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\n" ); document.write( " Answer:
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\n" ); document.write( " The distance between the two points (0, -1.5) and (4, 1) is exactly \"sqrt%2822.25%29\" units
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\n" ); document.write( " The approximate distance between the two points is about 4.7169905660283 units
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\n" ); document.write( " So again,
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\n" ); document.write( " Exact Distance: \"sqrt%2822.25%29\" units
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\n" ); document.write( " Approximate Distance: \"4.7169905660283\" units
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\n" ); document.write( "\n" ); document.write( "so, radius is \"r=4.72\"\r
\n" ); document.write( "\n" ); document.write( "equation of a circle in standard form: \r
\n" ); document.write( "\n" ); document.write( "\"%28x+-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x+-0%29%5E2+%2B+%28y-%28-1.5%29%29%5E2+=+%284.72%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2+%2B+%28y%2B1.5%29%5E2+=+22.28\"\r
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