document.write( "Question 779078: Suppose you have a supply of a 25% solution of alcohol and a 75% solution Of alcohol. How Many quarts of Each Should be mixed to produce 40 quarts that is 70% produce? I need help setting this problem up. \n" ); document.write( "
Algebra.Com's Answer #475065 by josmiceli(19441)\"\" \"About 
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Let \"+a+\" = quarts of 25% alcohol solution needed
\n" ); document.write( "Let \"+b+\" = quarts of 75% alcohol solution needed
\n" ); document.write( "---------------
\n" ); document.write( "(1) \"+a+%2B+b+=+40+\"
\n" ); document.write( "(2) \"+%28+.25a+%2B+.75b+%29+%2F+40+=+.7+\"
\n" ); document.write( "----------------------------
\n" ); document.write( "(2) \"+.25a+%2B+.75b+=+.7%2A40+\"
\n" ); document.write( "(2) \"+.25a+%2B+.75b+=+28+\"
\n" ); document.write( "(2) \"+25a+%2B+75b+=+2800+\"
\n" ); document.write( "Multiply both sides of (1) by \"+25+\" and subtract
\n" ); document.write( "(1) from (2)
\n" ); document.write( "(2) \"+25a+%2B+75b+=+2800+\"
\n" ); document.write( "(1) \"+-25a+-+25b+=+-1000+\"
\n" ); document.write( "\"+50b+=+1800+\"
\n" ); document.write( "\"+b+=+36+\"
\n" ); document.write( "and, since
\n" ); document.write( "(1) \"+a+%2B+b+=+40+\"
\n" ); document.write( "(1) \"+a+=+4+\"
\n" ); document.write( "---------------
\n" ); document.write( "4 quarts of 25% alcohol solution are needed
\n" ); document.write( "36 quarts of 75% alcohol solution are needed
\n" ); document.write( "---------------
\n" ); document.write( "check:
\n" ); document.write( "(2) \"+%28+.25%2A4+%2B+.75%2A36+%29+%2F+40+=+.7+\"
\n" ); document.write( "(2) \"+%28+1+%2B+27+%29+%2F+40+=+.7+\"
\n" ); document.write( "(2) \"+28+=+.7%2A40+\"
\n" ); document.write( "(2) \"+28+=+28+\"
\n" ); document.write( "OK
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