document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=779082>Question 779082</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a building in a city has a rectangular base. the length of the base measures 65 ft less than thrice the width. the perimeter of this base is 910 ft. what are the dimensions of the base? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #475063 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=475063\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a building in a city has a rectangular base. the length of the base measures 65 ft less than thrice the width. the perimeter of this base is 910 ft. what are the dimensions of the base?<BR>\n" );
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document.write( "Let w = width<BR>\n" );
document.write( "then from \"length of the base measures 65 ft less than thrice the width\"<BR>\n" );
document.write( "3w-65 = length<BR>\n" );
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document.write( "2(w + 3w-65) = 910<BR>\n" );
document.write( "2(4w-65) = 910<BR>\n" );
document.write( "4w-65 = 455<BR>\n" );
document.write( "4w = 520<BR>\n" );
document.write( "w = 130 feet (width)<BR>\n" );
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document.write( "Length then:<BR>\n" );
document.write( "3w-65 = 3(130)-65 = 390-65 = 325 feet (length)<BR>\n" );
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document.write( "dimensions of base:<BR>\n" );
document.write( "130 feet by 325 feet\r<BR>\n" );
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document.write( " </SPAN>\n" );
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