document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=779031>Question 779031</A>: <I><SPAN STYLE=\"word-break: break-all;\"> You have a spinner with numbers 1 through 12, using a simulation what is the probability of getting 3 odd numbers in a row? I did:<BR>\n" );
document.write( "1 3 5 7 9 11 which would be exactly half the numbers on the spinner. So 3 spins would be 1/2 x 3 and I ended up with 3/8 which is 37.5%<BR>\n" );
document.write( "Did I do this correctly? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #475047 by </B><A HREF=/tutors/aboutme.mpl?userid=1412><B>1412(5)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=1412><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=1412><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=475047\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Permutation(6,3) = 6!/(3! 3!) = 20 ==> Number of ways refer to 3 odds<BR>\n" );
document.write( "Permutation(12,3) = 12!/(3! 9!) = 220 ==> Number of the outcomes in the sample space<BR>\n" );
document.write( "the final answer = 20/220<BR>\n" );
document.write( "= 1/11\r<BR>\n" );
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