document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=778983>Question 778983</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi, I was just wondering if I set up my problem right. In a bicycle race, Lionel gives Robert a 500 m advantage. Also, Lionel agrees to start 15 min after Robert. If Lionel bikes at 17 km/h and Robert at 14 km/h, how long will it take Lionel after he starts biking to overtake Robert? This is what I did:<BR>\n" );
document.write( "14t=17(t-.25)<BR>\n" );
document.write( "14t=17t-4.25<BR>\n" );
document.write( "3t=4.25<BR>\n" );
document.write( "I got it takes about 1 hour and 24 min.<BR>\n" );
document.write( "Thanks. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #475032 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=475032\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Robert bikes at 14 Km/h for 15 min (1/4 hour) before Lionel starts, so 1/4 of 14 is 3.5 Km.  Also Lionel spots Robert 500m which is .5 Km we then have<BR>\n" );
document.write( "17t = 14t +3.5 +.5<BR>\n" );
document.write( "3t = 4<BR>\n" );
document.write( "t = 1 1/3 hours<BR>\n" );
document.write( "t = 1 hour and 20 minutes<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );