document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=779033>Question 779033</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Could you help me solve a/4 - a/3 = -1/2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #475022 by </B><A HREF=/tutors/aboutme.mpl?userid=waynest><B>waynest(281)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=waynest><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=475022\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 12(a/4) - 12(a/3) = 12(-1/2)<BR>\n" );
document.write( "3a -4a =-6-a = -6<BR>\n" );
document.write( "a = 6\r<BR>\n" );
document.write( "\n" );
document.write( "check<BR>\n" );
document.write( "(6/4) - (6/3) = -1/2<BR>\n" );
document.write( "(2/3) - 2 = -1/2<BR>\n" );
document.write( "(1.5) - 2 = -1/2<BR>\n" );
document.write( "-1/2 = -1/2 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );