document.write( "Question 778933: Pipe A can fill a tank in 7 hours more than pipe B can. If A is opened for as many hours as it would take B to fill a tank, B can complete the filling 5 hours. How long does it take each pipe, alone, to fill a tank? \n" ); document.write( "
Algebra.Com's Answer #474960 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Pipe A can fill a tank in 7 hours more than pipe B can. \n" ); document.write( " If A is opened for as many hours as it would take B to fill a tank, B can complete the filling 5 hours. \n" ); document.write( " How long does it take each pipe, alone, to fill a tank? \n" ); document.write( ": \n" ); document.write( "Let t = time required by pipe B alone \n" ); document.write( "then \n" ); document.write( "(t+7) = time required by pipe A \n" ); document.write( ": \n" ); document.write( "Let the completed job = 1; (a full tank) \n" ); document.write( ": \n" ); document.write( "A shared work equation, each pipe does a fraction of the job \n" ); document.write( "The two fractions add up to 1 \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "multiply equation by t(t+7), to clear the denominators, resulting in: \n" ); document.write( "t^2 + 5(t+7) = t(t+7) \n" ); document.write( "t^2 + 5t + 35 = t^2 + 7t \n" ); document.write( "Subtract t^2 from both sides \n" ); document.write( "5t + 35 = 7t \n" ); document.write( "35 = 7t - 5t \n" ); document.write( "35 = 2t \n" ); document.write( "t = 35/2 \n" ); document.write( "t = 17.5 hrs for B to fill the tank alone \n" ); document.write( "then \n" ); document.write( "17.5 + 7 = 24.5 hrs for A to do it \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this with a calc \n" ); document.write( " |