document.write( "Question 778871: The product of two consecutive integers is 71 more than the square of the preceding smaller integer. Find the numbers. \n" ); document.write( "
Algebra.Com's Answer #474958 by ramkikk66(644)\"\" \"About 
You can put this solution on YOUR website!
\r\n" );
document.write( "The product of two consecutive integers is 71 more than the square of the preceding smaller integer. Find the numbers.\r\n" );
document.write( "Ans:\r\n" );
document.write( "Let the integers be n and n+1. Then the preceding smaller integer is (n-1).\r\n" );
document.write( "It is given that\r\n" );
document.write( "\"n%2A%28n%2B1%29+=+%28n-1%29%5E2+%2B+71\"\r\n" );
document.write( "\"n%5E2+%2B+n+=+n%5E2+-+2%2An+%2B+1+%2B+71+=+n%5E2+-+2%2An+%2B+72\"\r\n" );
document.write( "Cancelling out n^2 and simplifying\r\n" );
document.write( "\"3%2An+=+72\"\r\n" );
document.write( "\"n+=+24\"\r\n" );
document.write( "The numbers are 24 and 25.\r\n" );
document.write( "Hope you got it :)\r\n" );
document.write( "
\n" ); document.write( "
\n" );