document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=778902>Question 778902</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Ernie avergaed 90 on her quizzes during the first part of the quarter and 60 on her quizzes during the second partof the quarter.  When she found out that her final average for the quarter was not 75, she went to argue with her teacher.  Give a possible explanation for Ernies misunderstanding. <BR>\n" );
document.write( "A. the averages from each half were incorrect<BR>\n" );
document.write( "B. The sum of the two averages must be divided by the total number of quizzes.<BR>\n" );
document.write( "C. The average of the two averages does not take into account different number of quizzes taken in each half.<BR>\n" );
document.write( "D. The final average is worth more than the average for each half.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #474952 by </B><A HREF=/tutors/aboutme.mpl?userid=psbhowmick><B>psbhowmick(878)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=psbhowmick><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=psbhowmick><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=474952\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D looks like a good option - weighted average. </SPAN>\n" );
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