document.write( "Question 66406: i don't understand substitution or elimination. \n" ); document.write( "
Algebra.Com's Answer #47494 by checkley71(8403)\"\" \"About 
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using the substitution method involves the following:
\n" ); document.write( "x+y=3 so x=3-y then we substitute (3-y) for x -n equation 2
\n" ); document.write( "2x+3y=8
\n" ); document.write( "2(3-y)+3y=8
\n" ); document.write( "6-2y+3y=8
\n" ); document.write( "y=8-2
\n" ); document.write( "y=2 solution now substitute 2 for y & solve for x
\n" ); document.write( "x+2=3
\n" ); document.write( "x=3-2
\n" ); document.write( "x=1 solution.
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\n" ); document.write( "using the elimination method involves the following:
\n" ); document.write( "2x-5y=11
\n" ); document.write( "3x+5y=4 adding the 2 equations we eliminate the y values & we get
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\n" ); document.write( "5x=15
\n" ); document.write( "x=15/5
\n" ); document.write( "x=3 solution
\n" ); document.write( "2*3-5y=11
\n" ); document.write( "6-5y=11
\n" ); document.write( "-5y=5
\n" ); document.write( "y=5/-5
\n" ); document.write( "y=-1 solution.
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