document.write( "Question 66660: PLease help to graph\r
\n" ); document.write( "\n" ); document.write( "y < 2 \r
\n" ); document.write( "\n" ); document.write( "5x + 3y > or equal to 12
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Algebra.Com's Answer #47491 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
y < 2
\n" ); document.write( "This isjust a horizontal line going thru +2 on the y axis, < 2 means the area of interest is below the line and not at the line\r
\n" ); document.write( "\n" ); document.write( "5x + 3y >= 12
\n" ); document.write( "Arrange the equation in the general \"y=\" form
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\n" ); document.write( "3y >= 12 - 5x
\n" ); document.write( "y >= 12/3 - (5/3)x
\n" ); document.write( "y >= 4 - (5/3)x
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\n" ); document.write( "Make a table of x values and the corresponding value for y:
\n" ); document.write( "An example for x = -3:
\n" ); document.write( " y = 4 - (5/3)(-3)
\n" ); document.write( " y = 4 + 5; a minus a minus is a plus, the 3's cancel
\n" ); document.write( " y = +9 when x = -3
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\n" ); document.write( "x | y
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\n" ); document.write( "-3| 9
\n" ); document.write( "0 | 4
\n" ); document.write( "+3|-1
\n" ); document.write( "Notice I picked some values which avoided the use of fractions, but this OK because it is a straight line and easy to plot this way.
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\n" ); document.write( "Your graph should look like this:
\n" ); document.write( "\"+graph%28+300%2C+200%2C+-6%2C+6%2C+-6%2C+10%2C+2%2C+4-%285%2F3%29x%29+\"
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\n" ); document.write( "Notice our equation says y => 4 - (5/3)x, this means the area of interest is at and above the green line in the graph.
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\n" ); document.write( "However, the y < 2 means it is below the red line, so the area bounded by these two equations would the triangular area at/above and to the right of the green line and below the red line. Does this make sense to you?
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