document.write( "Question 778647: A homing device left its home to deliver a message. On takeoff the device encountered a tailwind of 9 mph and made the delivery in 20 minutes. The return trip into the wind took 40 minutes. How fast could the device fly in still air? \n" ); document.write( "
Algebra.Com's Answer #474868 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
A homing device left its home to deliver a message.
\n" ); document.write( " On takeoff the device encountered a tailwind of 9 mph and made the delivery in 20 minutes.
\n" ); document.write( " The return trip into the wind took 40 minutes.
\n" ); document.write( " How fast could the device fly in still air?
\n" ); document.write( ":
\n" ); document.write( "Let s = speed in still air
\n" ); document.write( "then
\n" ); document.write( "(s+9) = relative speed with the wind
\n" ); document.write( "and
\n" ); document.write( "(s-9) = relative speed against
\n" ); document.write( ":
\n" ); document.write( "Change 20 min to 1/3 hr. Change 40 min to 2/3 hr
\n" ); document.write( ":
\n" ); document.write( "Write a distance equation, distance there and back are the same
\n" ); document.write( "\"2%2F3\"(s-9) = \"1%2F3\"(s+9)
\n" ); document.write( "multiply both sides by 3, resulting in:
\n" ); document.write( "2(s-9) = s + 9
\n" ); document.write( "2s - 18 = s + 9
\n" ); document.write( "2s -s = 9 + 18
\n" ); document.write( "s = 27 mph speed in still air
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Confirm this by finding the actual distances
\n" ); document.write( "\"2%2F3\"*(27-9) = 12 mi
\n" ); document.write( "\"1%2F3\"*(27+9) = 12 mi
\n" ); document.write( "
\n" );