document.write( "Question 778639: Given the arithmetic progression -1/6,1/12,1/3...find the 10th term and the sum of the 12 terms
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Algebra.Com's Answer #474832 by psbhowmick(878) $\"\"$ $\"About$

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The $\"n\"$ -th term for an A.P. series with first term $\"a\"$ and common difference $\"d\"$ is given by $\"t%5Bn%5D=a%2B%28n-1%29d\"$ .\r
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\n" ); document.write( "\n" ); document.write( "Here, $\"a=-1%2F6\"$ , $\"d+=+1%2F12-%28-1%2F6%29=1%2F12%2B1%2F6=3%2F12=1%2F4\"$ .
\n" ); document.write( " $\"t%5B10%5D=-1%2F6%2B%2810-1%29%281%2F4%29\"$
\n" ); document.write( " $\"t%5B10%5D=-1%2F6%2B9%2F4=%28-2%2B27%29%2F12=25%2F12\"$ \n" ); document.write( "

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