document.write( "Question 778620: F(x) = (x+2)/(x+3) where x is not equal to 0. Parentheses are not in the original problem, I included them to show what is over what. \n" ); document.write( "

Algebra.Com's Answer #474816 by Edwin McCravy(20055) $\"\"$ $\"About$

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F(x) = (x+2)/(x+3) where x is not equal to 0. Parentheses are not in the original problem, I included them to show what is over what.
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document.write( "I'm glad you put those parentheses there.  Most students would\r\n" );
document.write( "have written  \" x+2/x+3 \" which really means , an\r\n" );
document.write( "altogether different expression.\r\n" );
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document.write( "But you didn't state what you were to find.  I assume it is \r\n" );
document.write( "the domain and range.\r\n" );
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document.write( "The denominator x+3 must not equal 0, so\r\n" );
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document.write( "x+3 ≠ 0\r\n" );
document.write( "  x ≠ -3,  so we have a vertical asymptote at x = -3\r\n" );
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document.write( "The degree of the numerator and denominator are both 1, so\r\n" );
document.write( "the horizontal asymptote is\r\n" );
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document.write( "y = \r\n" );
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document.write( "y = \r\n" );
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document.write( "y = 1 , so we have a horizontal asymptote at y = 1\r\n" );
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document.write( "You also state \"x is not equal to 0\", so we must leave out the\r\n" );
document.write( "point (0,) and put an open circle there. The two asymptotes\r\n" );
document.write( "are in green:\r\n" );
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document.write( "So the domain is (-∞,-3)U(-3,0)U(0,∞) and\r\n" );
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document.write( "the range is (-∞,)U(,1)U(1,∞)\r\n" );
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document.write( "Edwin

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