document.write( "Question 66668: Please help to solve\r
\n" ); document.write( "\n" ); document.write( "square root of x + 2 = the square root of x +12
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Algebra.Com's Answer #47481 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
square root of x + 2 = the square root of x +12
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\n" ); document.write( "The use of brackets would sure help here, to let us know just exactly what the problems is.
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\n" ); document.write( "I am going to assume you mean:
\n" ); document.write( "SqRt(x) + 2 = SqRt(x + 12)
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\n" ); document.write( "[SqRt(x)+2]^2 = [SqRt(x+12)]^2; square both sides
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\n" ); document.write( "FOIL [SqRt(x)+ 2] [SqRt(x)+ 2] and you have:
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\n" ); document.write( "x + 4SqRt(x) + 4 = x + 12
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\n" ); document.write( "Get the radical on the left by itself:
\n" ); document.write( "4*SqRt(x) = x + 12 - x - 4
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\n" ); document.write( "4*SqRt(x) = +8
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\n" ); document.write( "Square both sides again:
\n" ); document.write( "16(x) = 64
\n" ); document.write( "x = 64/16
\n" ); document.write( "x = 4
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\n" ); document.write( "you can check this, substitute 4 x in the original equation:
\n" ); document.write( "SqRt(4) + 2 = SqRt(4 + 12)
\n" ); document.write( "2 + 2 = SqRt(16)
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\n" ); document.write( "If this problem was different from what I assumed, email me and we will see what we can do with it.
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