document.write( "Question 778562: Ten years ago, the sum of the ages of two sons was one third of their father’s age. One son is
\n" ); document.write( "two years older than the other and sum of their present ages is 14 years less than the father’s
\n" ); document.write( "present age. Find the present ages of all \n" ); document.write( "

Algebra.Com's Answer #474795 by stanbon(75887) $\"\"$ $\"About$

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Ten years ago, the sum of the ages of two sons was (1/3) of their father’s age.
\n" ); document.write( "One son is two years older than the other
\n" ); document.write( "and sum of their present ages is 14 years less than the father’s present age. Find the present ages of all
\n" ); document.write( "--------
\n" ); document.write( "Equations:
\n" ); document.write( "s1-10 + s2-10 = (1/3)f
\n" ); document.write( "s1 = s2+2
\n" ); document.write( "s1+s2 = f-14
\n" ); document.write( "---------------------
\n" ); document.write( "Simplify::
\n" ); document.write( "s1+s2-20 = (1/3)f
\n" ); document.write( "Sustitute for s1+s2
\n" ); document.write( "f-14 + (1/3)f
\n" ); document.write( "3f-42 = f
\n" ); document.write( "2f = 42
\n" ); document.write( "father's age is 21 years
\n" ); document.write( "----
\n" ); document.write( "s1+s2 = 21-14 = 7
\n" ); document.write( "---
\n" ); document.write( "Substitute for s1 to get:
\n" ); document.write( "s2+2 + s2 = 7
\n" ); document.write( "2s2 = 5
\n" ); document.write( "s2 = 2 1/2 years
\n" ); document.write( "Then s1 = 4 1/2 years
\n" ); document.write( "=====================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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