document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=778567>Question 778567</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two angles are complementary.one angle is 42 degrees more than one half the other. find the angles.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #474789 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=474789\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> two angles are complementary.one angle is 42 degrees more than one half the other. find the angles.<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "x + y = 90 degrees<BR>\n" );
document.write( "x = (1/2)y+42<BR>\n" );
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document.write( "Substitute and solve for \"y\":<BR>\n" );
document.write( "(1/2)y + 42 + y = 90<BR>\n" );
document.write( "(3/2)y = 48<BR>\n" );
document.write( "y = 32<BR>\n" );
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document.write( "Solve for \"x\":<BR>\n" );
document.write( "x = (1/2)32+42 = 16+42 = 58<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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