document.write( "Question 778504: Half the supplement of an angle is 18 less than four times the complement of the angle. Set up and solve an equation to find the measure of the angle, the complement, and the supplement \n" ); document.write( "

Algebra.Com's Answer #474765 by lwsshak3(11628) $\"\"$ $\"About$

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Half the supplement of an angle is 18 less than four times the complement of the angle. Set up and solve an equation to find the measure of the angle, the complement, and the supplement
\n" ); document.write( "let x= measure of the angle
\n" ); document.write( "supplement=180-x
\n" ); document.write( "complement=90-x
\n" ); document.write( "..
\n" ); document.write( " $\"%28180-x%29%2F2=4%2890-x%29-18\"$
\n" ); document.write( "LCD:2
\n" ); document.write( " $\"%28180-x%29=8%2890-x%29-36\"$
\n" ); document.write( "180-x=720-8x-36
\n" ); document.write( "7x=720-36-180
\n" ); document.write( "7x=504
\n" ); document.write( "x=72
\n" ); document.write( "180-x=108
\n" ); document.write( "90-x=18
\n" ); document.write( "measure of the angle=72º
\n" ); document.write( "supplement=108º
\n" ); document.write( "complement=18º \n" ); document.write( "

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