document.write( "Question 66786: 1+ or - 3i/2= ?????????????????
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document.write( "How do you do it? Please help , Thank You
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document.write( "(This question didn't come out of a book, our teacher gave it to us on a paper.) \n" );
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Algebra.Com's Answer #47476 by stanbon(75887) ![]() You can put this solution on YOUR website! Find the equation if the roots are \n" ); document.write( "1+ or - 3i/2 \n" ); document.write( "If 1+(3/2)i is a root, (x-1-(3/2)i) is a factor \n" ); document.write( "If 1-(3/2)i is a root, (x-1+(3/2)i) is a factor \n" ); document.write( "These factors are arranged in the form (a-b)(a+b) \n" ); document.write( "whose product is a^2-b^2. So you get: \n" ); document.write( "y=((x-1)-(3/2)i)((x-1)+(3/2)i) \n" ); document.write( "y=[(x-1)^2 - (3/2 i)^2] \n" ); document.write( "y=[x^2-2x+1+(9/4)] \n" ); document.write( "y=[x^2-2x+13/4] \n" ); document.write( "or \n" ); document.write( "y=(1/4)x^2-(1/2)x+13 \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |