document.write( "Question 778521: I need to factor 125-x^3
\n" ); document.write( "would that be (5-x)^3?
\n" ); document.write( "

Algebra.Com's Answer #474740 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\r
\n" ); document.write( "\n" ); document.write( "\"125-x%5E3\" Start with the given expression.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%285%29%5E3-%28x%29%5E3\" Rewrite \"125\" as \"%285%29%5E3\". Rewrite \"x%5E3\" as \"%28x%29%5E3\".\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%285-x%29%28%285%29%5E2%2B%285%29%28x%29%2B%28x%29%5E2%29\" Now factor by using the difference of cubes formula. Remember the difference of cubes formula is \"A%5E3-B%5E3=%28A-B%29%28A%5E2%2BAB%2BB%5E2%29\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%285-x%29%2825%2B5x%2Bx%5E2%29\" Multiply\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "-----------------------------------\r
\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "\n" ); document.write( "So \"125-x%5E3\" factors to \"%285-x%29%2825%2B5x%2Bx%5E2%29\".\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "In other words, \"125-x%5E3=%285-x%29%2825%2B5x%2Bx%5E2%29\"
\n" ); document.write( "
\n" ); document.write( "
\n" );