document.write( "Question 778466: At the Golden Oldies Theater,tickets for adults cost $5.50 and tickets for children at $3.50. How many of each kind of ticker were purchased if 21 tickets were bought for $83.50? \n" ); document.write( "

Algebra.Com's Answer #474733 by mananth(16946) $\"\"$ $\"About$

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x= Number of adult tickets
\n" ); document.write( "y= Number of child tickets
\n" ); document.write( "
\n" ); document.write( "1.00 x + 1.00 y = 21.00 .............1
\n" ); document.write( "Total value
\n" ); document.write( "5.50 x + 3.50 y = 83.50 .............2
\n" ); document.write( "Eliminate y
\n" ); document.write( "multiply (1)by -3.50
\n" ); document.write( "Multiply (2) by 1.00
\n" ); document.write( "-3.50 x -3.50 y = -73.50
\n" ); document.write( "5.50 x + 3.50 y = 83.50
\n" ); document.write( "Add the two equations
\n" ); document.write( "2.00 x = 10.00
\n" ); document.write( "/ 2.00
\n" ); document.write( "x = 5.00
\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "1.00 x + 1.00 y = 21.00
\n" ); document.write( "5.00 + y = 21.00
\n" ); document.write( " y = 21.00 -5.00
\n" ); document.write( " y = 16.00
\n" ); document.write( " y = 16.00
\n" ); document.write( "x= 5 Number of adult tickets
\n" ); document.write( "y= 16 Number of child tickets
\n" ); document.write( " \n" ); document.write( "

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