document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=778030>Question 778030</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi I have a question where I have step one has 1 block, step 2 has 4 blocks, step 3 has 7 blocks and so on. I know it progresses by 3 but I need 2 formulas on how to get them besides 1+3(n-1) and<BR>\n" );
document.write( " 3n-2 because I have those <BR>\n" );
document.write( "Please help me<BR>\n" );
document.write( "  -Ron </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #474722 by </B><A HREF=/tutors/aboutme.mpl?userid=sofiyac><B>sofiyac(983)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sofiyac><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sofiyac><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=474722\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1 2 3<BR>\n" );
document.write( "1 4 7<BR>\n" );
document.write( "the proper way to describe the series would be 3n-2, you could factor out 3 if you want a different way of writing it<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%28n-2%2F3%29 ALIGN=MIDDLE  ALT=\"3%28n-2%2F3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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