document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=778462>Question 778462</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how much of an alloy that is 30% copper should be mixed with 200 ounces of an alloy that is 60% copper in order to get an alloy that is 40% copper? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #474717 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=474717\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ---	percent	----------------	Amount									<BR>\n" );
document.write( "Copper Alloy I	60	----------------			200	Oz						<BR>\n" );
document.write( "copper qlloy II	30	----------------			x	Oz						<BR>\n" );
document.write( "Mixture	40	----------------	200	+	x	Oz						<BR>\n" );
document.write( "												<BR>\n" );
document.write( "60	*	200	+	30	x	=	40	(	200	+	x	)<BR>\n" );
document.write( "12000	+	30	x	=	8000	+	40	x				<BR>\n" );
document.write( "30	x		-40	x	=	-12000	+	8000				<BR>\n" );
document.write( "-10	x	=	-4000									<BR>\n" );
document.write( "/	-10											<BR>\n" );
document.write( "x	=	400		Oz	copper qlloy II							<BR>\n" );
document.write( "												<BR>\n" );
document.write( "m.ananth@hotmail.ca												<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );