document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=778138>Question 778138</A>: <I><SPAN STYLE=\"word-break: break-all;\"> use elimination to find all points of intersection of the graphs of 3x+2y=10 and 2x+5y=3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #474713 by </B><A HREF=/tutors/aboutme.mpl?userid=sofiyac><B>sofiyac(983)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sofiyac><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sofiyac><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=474713\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x+2y=10 multiply this one by -2<BR>\n" );
document.write( "2x+5y=3 multiply this one by 3, then add the two new equations<BR>\n" );
document.write( "-  <BR>\n" );
document.write( "-6x-4y=-20<BR>\n" );
document.write( "6x+15y=9   now add them<BR>\n" );
document.write( "-----------<BR>\n" );
document.write( "11y=-11 divide each side by 11<BR>\n" );
document.write( "y=-1 next plug that into either of the original equations and solve for x, i'm going to work with the first one<BR>\n" );
document.write( "3x+2(-1)=10<BR>\n" );
document.write( "3x-2=10 add 2 to each side<BR>\n" );
document.write( "3x=12 divide each side by 3<BR>\n" );
document.write( "x=4<BR>\n" );
document.write( "(4,-1) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );