document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=778476>Question 778476</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the graph of y=(ax+b)/(x+c) has a horizontal asymptote y=2 and a vertical asymptote x=-3, then a+c=?\r<BR>\n" );
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document.write( "a. -5<BR>\n" );
document.write( "b. -1<BR>\n" );
document.write( "c. 0<BR>\n" );
document.write( "d. 1<BR>\n" );
document.write( "e. 5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #474681 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=474681\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the graph of y=(ax+b)/(x+c) has a horizontal asymptote y=2 and a vertical asymptote x=-3, then a+c=? <BR>\n" );
document.write( "a. -5<BR>\n" );
document.write( "b. -1<BR>\n" );
document.write( "c. 0<BR>\n" );
document.write( "d. 1<BR>\n" );
document.write( "e. 5<BR>\n" );
document.write( "***<BR>\n" );
document.write( "To find the vertical asymptote, set denominator=0, then solve for x:<BR>\n" );
document.write( "x+c=0<BR>\n" );
document.write( "x=-c=-3 (vertical asymptote)<BR>\n" );
document.write( "c=3<BR>\n" );
document.write( "..<BR>\n" );
document.write( "If degree of numerator=degree of denominator, as in this case:<BR>\n" );
document.write( "Horizontal asymptote= quotient of lead coefficient of numerator divided by lead coefficient of denominator.<BR>\n" );
document.write( "horizontal asymptote=a/1=2<BR>\n" );
document.write( "a=2<BR>\n" );
document.write( "a+c=5 </SPAN>\n" );
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