document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=778476>Question 778476</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the graph of y=(ax+b)/(x+c) has a horizontal asymptote y=2 and a vertical asymptote x=-3, then a+c=?\r<BR>\n" );
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document.write( "a. -5<BR>\n" );
document.write( "b. -1<BR>\n" );
document.write( "c. 0<BR>\n" );
document.write( "d. 1<BR>\n" );
document.write( "e. 5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #474680 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=474680\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the graph of y=(ax+b)/(x+c) has a horizontal asymptote y=2 and a vertical asymptote x=-3, then a+c=?<BR>\n" );
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document.write( "The HA = a/1 = a = 2<BR>\n" );
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document.write( "The VA = -c = -3<BR>\n" );
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document.write( "So a + c = 2+3 = 5<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( " <BR>\n" );
document.write( "a. -5<BR>\n" );
document.write( "b. -1<BR>\n" );
document.write( "c. 0<BR>\n" );
document.write( "d. 1<BR>\n" );
document.write( "e. 5<BR>\n" );
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