document.write( "Question 778481: RIGHT TRIANGLE TRIGONOMETRY:
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document.write( "The top of a 25-foot ladder is sliding down a vertical wall at a constant rate of 3 feet per minute. When the top of the ladder is 7 feet from the ground, how far is the bottom of the ladder from the wall? \r
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Algebra.Com's Answer #474675 by algebrahouse.com(1659)![]() ![]() You can put this solution on YOUR website! A right triangle is formed with a height of 7 ft (up the wall) and a hypotenuse of 25 ft (the ladder).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a² + b² = c² {the pythagorean theorem} \n" ); document.write( "7² + b² = 25² {a and b are the legs and c is the hypotenuse} \n" ); document.write( "49 + b² = 625 {evaluated the exponents} \n" ); document.write( "b² = 576 {subtracted 49 from each side} \n" ); document.write( "b = 24 {took the square root of each side}\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the bottom of the ladder is 24 ft from the wall \n" ); document.write( " For more help from me, visit: www.algebrahouse.com \n" ); document.write( " \n" ); document.write( " |