document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=778475>Question 778475</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The measure of the complement of an angle is two hundred ten less than five times the measure of the angle. Find the measure of both angles. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #474665 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=474665\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Complementary angles add up to 90°.\r<BR>\n" );
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document.write( "x = the angle<BR>\n" );
document.write( "90 - x = its complement\r<BR>\n" );
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document.write( "90 - x = 5x - 210 {the complement is equal to 210 less than five times the angle}<BR>\n" );
document.write( "90 = 6x - 210 {added x to each side}<BR>\n" );
document.write( "300 = 6x {added 210 to each side}<BR>\n" );
document.write( "x = 50 {divided each side by 6}<BR>\n" );
document.write( "90 - x = 40 {substituted 90, in for x, into 90 - x}\r<BR>\n" );
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document.write( "the angle is 50°<BR>\n" );
document.write( "the complement is 40°<BR>\n" );
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