document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=778472>Question 778472</A>: <I><SPAN STYLE=\"word-break: break-all;\"> three consecutive numbers are added together and then their sum is multiplied by 3<BR>\n" );
document.write( "which equation(s) applies to this<BR>\n" );
document.write( "1)3x + 3x + 1 + 3x + 2<BR>\n" );
document.write( "2)3x + 3x + 3 + 3x + 6<BR>\n" );
document.write( "3)3x + 3(x + 1) + 3(x + 2)<BR>\n" );
document.write( "4)x + x + 3 + x + 6  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #474662 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=474662\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Three consecutive numbers would be:\r<BR>\n" );
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document.write( "x = first<BR>\n" );
document.write( "x + 1 = second<BR>\n" );
document.write( "x + 2 = third   {consecutive numbers increase by 1}\r<BR>\n" );
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document.write( "x + x + 1 + x + 2 = the sum<BR>\n" );
document.write( "3(x + x + 1 + x + 2)    {multiplied the sum by 3}<BR>\n" );
document.write( "3x + 3x + 3 + 3x + 6   {used distributive property}\r<BR>\n" );
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document.write( "3.)   3x + 3x + 3 + 3x + 6<BR>\n" );
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