document.write( "Question 778461: Write the function in vertex form.
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Algebra.Com's Answer #474653 by Edwin McCravy(20055)\"\" \"About 
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document.write( "We want to get y = a(x-h)²+k \r\n" );
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document.write( "y = x²-3x+6 in the form \r\n" );
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document.write( "Put brackets around the first two terms on the\r\n" );
document.write( "right,\r\n" );
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document.write( "y = [x²-3x]+6\r\n" );
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document.write( " and since the coefficient of x² is 1 put 1\r\n" );
document.write( "in front of the parentheses. Normally you\r\n" );
document.write( "would factor out the coefficient of x²:\r\n" );
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document.write( "y = 1[x²-3x]+6\r\n" );
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document.write( "We complete the square inside the brackets:\r\n" );
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document.write( "1. Multiply the coefficient of x, which is -3\r\n" );
document.write( "   by \"1%2F2\", getting \"-3%2F2\".\r\n" );
document.write( "2. Square \"-3%2F2\" getting \"%28-3%2F2%29%5E2\" = \"9%2F4\"\r\n" );
document.write( "3. Add \"%22%22%2B9%2F4-9%2F4\", which is really 0, inside the\r\n" );
document.write( "   brackets:\r\n" );
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document.write( "y = 1[x²-3x+\"9%2F4\"-\"9%2F4\"]+6\r\n" );
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document.write( "Factor the first three terms inside the bracket like this\r\n" );
document.write( "             x²-3x+\"9%2F4\" = (x-\"3%2F2\")(x-\"3%2F2\") = (x-\"3%2F2\")²\r\n" );
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document.write( "y = 1[(x-\"3%2F2\")²-\"9%2F4\"]+6\r\n" );
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document.write( "Remove the bracket\r\n" );
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document.write( "y = 1(x-\"3%2F2\")²-\"9%2F4\"+6 \r\n" );
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document.write( "Write the 6 as \"24%2F4\"\r\n" );
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document.write( "y = 1(x-\"3%2F2\")²-\"9%2F4\"+\"24%2F4\"\r\n" );
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document.write( "y = 1(x-\"3%2F4\")²+\"15%2F4\" \r\n" );
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document.write( "y = a(x-h)²+k\r\n" );
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document.write( "The vertex is (h,k) = (\"3%2F4\",\"15%2F4\")\r\n" );
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document.write( "Edwin
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