document.write( "Question 778430: Factor the expression:\r
\n" ); document.write( "\n" ); document.write( "125a^3-8b^3 \n" ); document.write( "
Algebra.Com's Answer #474631 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"125a%5E3-8b%5E3\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"%285a%29%5E3-%282b%29%5E3\" Rewrite \"125a%5E3\" as \"%285a%29%5E3\". Rewrite \"8b%5E3\" as \"%282b%29%5E3\".\r
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\n" ); document.write( "\n" ); document.write( "\"%285a-2b%29%28%285a%29%5E2%2B%285a%29%282b%29%2B%282b%29%5E2%29\" Now factor by using the difference of cubes formula. Remember the difference of cubes formula is \"A%5E3-B%5E3=%28A-B%29%28A%5E2%2BAB%2BB%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%285a-2b%29%2825a%5E2%2B10ab%2B4b%5E2%29\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "\n" ); document.write( "So \"125a%5E3-8b%5E3\" factors to \"%285a-2b%29%2825a%5E2%2B10ab%2B4b%5E2%29\".\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"125a%5E3-8b%5E3=%285a-2b%29%2825a%5E2%2B10ab%2B4b%5E2%29\"
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