document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=778380>Question 778380</A>: <I><SPAN STYLE=\"word-break: break-all;\"> PLEASE TUTORS,I NEED HELP FOR THIS PROBLEM.........A man is four times as old as his son. In 10 years time,the man's age will be twice that of his son.how old is the man and son at present? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #474577 by </B><A HREF=/tutors/aboutme.mpl?userid=psbhowmick><B>psbhowmick(878)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=psbhowmick><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=psbhowmick><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=474577\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the age of the father be X and that of the son be Y.\r<BR>\n" );
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document.write( "X = 4Y _____ (1)\r<BR>\n" );
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document.write( "X+10 = 2(Y+10) _____ (2)\r<BR>\n" );
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document.write( "Substituting for X from (1) into (2)<BR>\n" );
document.write( "4Y + 10 = 2Y + 20<BR>\n" );
document.write( "2Y = 10<BR>\n" );
document.write( "Y = 5\r<BR>\n" );
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document.write( "So, X = 4*5 = 20\r<BR>\n" );
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document.write( "So present age of father is 20 and that of son is 5.\r<BR>\n" );
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document.write( "It looks odd!!! </SPAN>\n" );
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