document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=778241>Question 778241</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A merchant blends tea that sells for $4.95 a pound with tea that sells for $2.55 a pound to produce 60 lb of a mixture that sells for $3.75 a pound. How many pounds of each type of tea does the merchant use in the blend? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #474495 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=474495\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 	Price	----------------			quantity									<BR>\n" );
document.write( "Tea type I	4.95	----------------			x	pounds								<BR>\n" );
document.write( "Tea type II	2.55	------	60	-	x	pounds								<BR>\n" );
document.write( "Mixture	3.75	----------------	60											<BR>\n" );
document.write( "	60													<BR>\n" );
document.write( "4.95	x	+	2.55	(	60	-	x	)	=	225				<BR>\n" );
document.write( "4.95	x	+	153	-	2.55	x	=			225				<BR>\n" );
document.write( "4.95	x	-	2.55	x			=	225	-	-153				<BR>\n" );
document.write( "2.4	x			=	72									<BR>\n" );
document.write( "/	2.4													<BR>\n" );
document.write( "	x			=	30		pounds			4.95%		Tea type I		<BR>\n" );
document.write( "					30		pounds			2.55%		Tea type II		<BR>\n" );
document.write( "														<BR>\n" );
document.write( "m.ananth@hotmail.ca														<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );