document.write( "Question 778151: I need to know if this is identity or contradication?\r
\n" ); document.write( "\n" ); document.write( "2q - 3 ( q - 5 ) = 5 ( q + 2 ) - 7
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Algebra.Com's Answer #474443 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"2q-3%28q-5%29=5%28q%2B2%29-7\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"2q-3q%2B15=5q%2B10-7\" Distribute.\r
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\n" ); document.write( "\n" ); document.write( "\"-q%2B15=5q%2B10-7\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"-q%2B15=5q%2B3\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"-q=5q%2B3-15\" Subtract \"15\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"-q-5q=3-15\" Subtract \"5q\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"-6q=3-15\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"-6q=-12\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"q=%28-12%29%2F%28-6%29\" Divide both sides by \"-6\" to isolate \"q\".\r
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\n" ); document.write( "\n" ); document.write( "\"q=2\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"q=2\" \r
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\n" ); document.write( "\n" ); document.write( "Since there is exactly one solution, this means that this is neither an identity nor a contradiction.
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